-1.9t^2+56t+30=0

Solution for -1.9t^2+56t+30=0 equation:

-1.9t^2+56t+30=0

a = -1.9; b = 56; c = +30;
Δ = b2-4ac
Δ = 562-4·(-1.9)·30
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-58}{2*-1.9}=\frac{-114}{-3.8}
=+30
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+58}{2*-1.9}=\frac{2}{-3.8}
=-2/3.8
$